Mintmaster
Veteran
Why not? I am simply determining average acceleration. I could probably give you a proof with the mean value theorem or something, but if the average is lower for 100-0 than 60-0, then from 100-60 it has to be slower. 100-0 has times, and they match the calculations from the distances within a tenth of a second or so. Cyan's data above for the F1 car also matches. 130 to 0 in 55 metres calculates to 1.89 seconds. t = 2*d/v (for this scenario, assuming constant acceleration).Mintmaster, you cannot use distance traveled when comparing breaking at different speeds the way you are if you don't have the time it took to stop.
Indeed, so I don't know why you brought it up. Two different publications on different tracks with different cars (even if the same model) is a pretty crappy experiment. I don't know what's so hard for you to accept about the data I showed. Threshold breaking is close to constant acceleration, and the equations are very simple.I'll admit, not the greatest example since the conditions were likely different.
Uhh, what? How is that "likewise"? If you need more energy at high speed to accelerate, why do you need less resistance to decelerate? You stuck in the world of Aristotelian physics?For example, the amount of energy spent to move an object from 50mph to 60 is much less then 145 to 155.
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Likewise the amount of resistance needed to slow an object moving at a very fast speed(155 to 95mph) is less then you need to slow the same object down from 60 mph to zero.
As I said before, you have to dissipate 4 times the energy in the former breaking scenario than the latter.
If you are travelling at 150 mph and go into neutral, how long will it take to slow down to 100 mph? Maybe 20 seconds or so? The retarding force is a small fraction of what can be achieved by the brakes.Sorry i dont want to sound like an ass but i thought this was common sense. More wind/air resistance plus more friction(tires to asphalt, axles and anything else on the car having to maintain a higher speed) = more energy consumed to maintain speed, thus less energy to decrease your speed by the same amount.
You need more power to fast even in the frictionless confines of deep space. P=Fv. E=M*V^2. It's physics.You need more power to go fast for a reason.
Anyway, you are completely missing the point. I am not saying that it's impossible for the Audi R8 to decelerate faster from 155 to 95 than from 60 to 0. The point is that the deceleration is roughly the same. It's going to be around 1g, not 1.6 or higher for this car without F1 style downforce.
Yet again, people aren't paying attention to my posts. I already said above that faster deceleration at higher speeds only happens with high downforce. You're preaching to the choir.phat said:However, Arwin brought up the issue of cars with net downforce at speed