The observer would still emit an electromagnetic field
A passive background EM field isn't going to affect the results. I was suggesting shooting something through an EM field to measure it, but of course you're then shooting photons at the particle. Some insight into what the detector is actually doing would be helpful!
I remain convinced that seeing is a completely passive activity, but as I said I'm no noble prize here.
Only because there's no Nobel Prize for Gorgeousness.
a) everyone can conduct the same experiment at home with the exact same pattern emerging, namely with light (in the video first example)
That's not the experiment.
Point B (shooting with atoms) is where the mystery lies, yes?
There are two issues. 1) Why does a particle behave like a wave and create the interference pattern? 2) Why does it stop behaving like a wave when the detector is engaged?
And the mystery is directly with how the "detector" influences either the pattern emerging or not. So I therefore conclude that the detector plays a significant role in how the atoms behave.
Quantum physics theories suggest that events only 'happen' when observed, and before they are observed they are a collection of probabilities (as I understand it, although I'm no expert). One of the theories to this experiment is that the particle, when launched, exists as a set of probable trajectories, and these are resolved when the particle is detected. If the particle isn't detected, the probabilities interact as if a wave, and the detection then resolves the trajectory at the point of impact on the surface, after the wave interaction. Or some-such. The principle being that the results are extremely alien to conventional human-level physics and cause-and-effect interactions.
In Point A, it is said that the pattern emerges because light that passes through reflects, bounces and cancels each other out.
Nope. It's not about particles, but waves. Light behaves as both. We know absolutely that there is a particle, a photon, with mass, that moves. But we also know this particle behaves as a wave, not as a particle.
To me, the most natural explanation is that there is a 'field' (n dimensional aspect, possibly outside the conventional barriers of space-time and yet with a measurable affect on space at least) defining the path of the photon, and this field acts similar to water. It will have high and low pressure areas creating waves, and photons will follow the paths of these pressure waves. Various scientists over the years have suggested theories of fields and such helping to describe various principles, but we can't detect them. We also may never be able to detect them, and can only theorise their existence based on experimental tests of the theory. And the behaviour of such fields may be basically incomprehensible to the human mind - we need to deconstruct them to analogy or express them in a language of our creation (maths) that may be imperfect to their description.
If we apply that theory to this experiment, the field posses a wave that the particle is following. The field exists with its interference patterns whether a particle is present or not. When a particle is launched, it follows the field, so has 'knowledge' of the bigger picture (because the bigger picture is defined by the field). If so, the question becomes one of affecting this field with the detector and removing the waves, or of affecting the particle with the detector and having it ignore the field. The niceness of this theory is it works for particles and photons, because both are masses following the dictates of the field.