Btw, found a couple of links:
http://www.newton.dep.anl.gov/askasci/chem03/chem03534.htm
http://www2.yk.psu.edu/~jhb3/cotw06.htm
Please note that while in the first link, the person states that there is no loss of mass in chemical reactions, if you read his first explaination, you may note that what he actually means is that the loss of mass is so small as to be negligible for the reactions involved.
One thing he misses, however, is that the equivalence of mass and energy is much more important in high-energy physics than it is in nuclear physics.
In nuclear physics, this equivalence is used as a method to calculate the energy output of a nuclear reaction: you take the mass of the components of the reaction, then of the individual resultants. Take the difference, and that's the amount of energy released in the reaction. In principle one could do a similar thing with chemical reactions, though it'd be much cheaper just to react the substances and find the result than to concoct an extremely careful experiment in measuring the mass difference.
In high-energy physics, however, this equivalence takes on a whole new meaning: physicists make use of the equivalence of mass and energy as a process for creating particles. Basically, the idea is this: it isn't mass that is conserved, but rather energy. Colliding a proton and an anti-proton at very high energies (today we're doing it in the range of 1000 times the mass-energy of the proton), and the resulting reaction can create basically anything that holds with all that is conserved for the particular force that mediates the interaction.
As a side comment, it turns out that all forces basically must conserve energy because all forces are independent of time. That is to say, no force of which we are aware changes its strength or properties as time passes. Mathematically, it turns out that this invariance in time translates to the conservation of energy in reactions involving this force.