C Cartoon Corpse Veteran Sep 9, 2005 #21 your first equivalence: (1/3)k(k+1)(k+2) + (k+1)(k+2)= (k/3+1)(k+1)(k+2) Click to expand... how is that equivalentl?
your first equivalence: (1/3)k(k+1)(k+2) + (k+1)(k+2)= (k/3+1)(k+1)(k+2) Click to expand... how is that equivalentl?
X _xxx_ Banned Sep 9, 2005 #22 Cartoon Corpse said: your first equivalence: how is that equivalentl? Click to expand... First (1/3)k = k/3, than it's (k/3)[(k+1)(k+2)] + 1[(k+1)(k+2)]. The rest should be clear, I hope
Cartoon Corpse said: your first equivalence: how is that equivalentl? Click to expand... First (1/3)k = k/3, than it's (k/3)[(k+1)(k+2)] + 1[(k+1)(k+2)]. The rest should be clear, I hope
C Cartoon Corpse Veteran Sep 9, 2005 #23 yep got it. been about 15 years since i had an algebra quiz. and as you know alot of us in life don't maintain that skill in our day to day existence.
yep got it. been about 15 years since i had an algebra quiz. and as you know alot of us in life don't maintain that skill in our day to day existence.