The aspect ratio for that DDR chip does not look like 3:4, it looks closer to 1:2, which is closer to 9:14. One of you is using 9:12 and the other 9:14, which is the difference in area. Based on my pixel count and using 9:14 which looks closer to the actual pic, that gets me 414mm^2.
Without the real size of the DDR chip, it is a error prone calculation.
Edit: spec sheet
http://www.micron.com/parts/dram/ddr3-sdram/mt41j256m16ha-093
They say several sizes, up to 10mmx14mm, which is the "96-ball" x16 Rev D, with Rev E being 9x14mm.
I'm guessing the Rev E is the latest for PC-2133 4Gb chips, which is 9x14mm, so this thing is over 400mm^2?
Without the real size of the DDR chip, it is a error prone calculation.
Edit: spec sheet
http://www.micron.com/parts/dram/ddr3-sdram/mt41j256m16ha-093
They say several sizes, up to 10mmx14mm, which is the "96-ball" x16 Rev D, with Rev E being 9x14mm.
I'm guessing the Rev E is the latest for PC-2133 4Gb chips, which is 9x14mm, so this thing is over 400mm^2?
Last edited by a moderator: