transistor count
Hello all,
Just have a question for Jaws really....
I noticed that you think the die size for the PS3 chip will about 290 - 300mm sq.... @ 65nm.
After reading an article at the inq about intels MONTECITO / 580Sqmm / 90nm, 1.72 billion transistor chip, it got me thinking.
source :
http://www.the-inquirer.net/?article=18345
I wanted to calculate how many transistors the CELL chip would have at a 300mm sq @ 65nm
first I calculated what area shrink would be from 90nm to 65nm :
90*90 = 8100 (multiplies out the surface area)
65*65 = 4225 (multiplies out the surface area)
8100 / 4225 = 1.9172 (the result is the value I need to divide the die size by.)
So am i correct in saying that if you took a 1.72 billion transistor chip built on 90nm process (that meseaures 580mm sq) and shrunk it down to 65nm, you get :
580 * 580 = 336400 (multiplies out the surface area)
336400 / 1.91 = 175464 (divides the surface area by required factor)
square root of 175464 = 418.9mm sq (resulting die size)
so a 1.72 billion transistor chip @ 65 nm has a 418.9mm sq size chip. so now to reduce the transistor count to make it fit on 300mm sq.
418.9 * 418.9 = 175477.21 (multiplies out the surface area of the oversized chip)
300 * 300 = 90000 (multiplies out the surface area of the required die size)
175477.21 / 90000 = 1.95 ( the division required for transistor reduction)
1.72 billion / 1.95 = 882 million
I therefore conclude that the CELL chip, according to your estimates of die size and in accordance with transistor counts from intel the cell will contain
(around) 882 million transistors. !!
Have I done somthing really silly, are my calculations going in the wrong direction.
DO you agree or disagree?