MfA said:
Hmm? If some math genious figured out calculus without ever thinking about trigonometry it wouldn't change a thing about the solutions ... he would name them differently, but they'd look the same on a graph.
Sure it could change the solutions. The differential equation that sin/cos functions are often quoted as the solutions of is the equation:
(d/dx)^2 f(x) + C * f(x) = 0
...and there are many ways to formulate the result, since any linear combination of solutions will be a solution. We often use sin/cos functions as solutions because of the history of sin/cos functions. There isn't any other reason than historical that we use them as solutions.
A more obvious solution to the above differential equation is actually:
f(x) = A*e^(ikx) + B*e^(-ikx)
...where k = 1/sqrt(C) and A and B are any two constants.
As for their definition in geometry, it is far from a natural one. That the relationship between angles defined to be linear along a circle and the sides of a right triangle could be used to solve problems with arbitrary triangles was a pretty big leap ... and without that leap such a definition of angles and their relation with right triangles is pretty arbitrary and irrelevant. Harmonic oscillations turn up everywhere, it's occurence in trigonometry is as haphazard as anywhere else.
My point was that the definition in geometry is directly tied to its history. So I think it makes the most sense as a way to define the sin/cos functions, most particularly when introducing the concept to new students.
Hell, in the end we actually need them for calculus ... whereas you only need a couple of algebraic relations between trigonometric functions to solve trigonometric problems (you don't actually need to have a calculable definition). Kinda funny that you don't need the actual trigonometric functions for trigonometry.
Well, actually, if you decide to take the leap to complex numbers there is no need for sin/cos functions in calculus at all, most particularly since:
sin(x) = (e^ix - e^-ix)/2i
cos(x) = (e^ix + e^-ix)/2
Edit: Or, more compactly:
sin(x) = Im(e^ix)
cos(x) = Re(e^ix)