So far I haven't undestood my logic error guys, help me out.
Samsung say their 128mbit card can do 4GB/sec (regardless of whether the RAM frequency was say 32 GHz on a 1 bit bus or 32 MHz on a 1,024 bit bus).
http://www.samsungelectronics.com/news/device_solution/com_news_1026373517250_001600.html
Seoul, Korea – July 10, 2002: Samsung Electronics Co, Ltd. introduces the industry’s first graphics memory chip using the next-generation DDR II specifications. Samsung’s new graphics chip is available in 128Mb density and boasts a data transmission rate of 1-GigaHertz and higher. The device is capable of transmitting 4-Gigabytes of data per second and is ideally suited for systems that require high memory speed and performance such as 3D graphics, gaming and network applications.
Well I guess you'd need 8 seperate 128 Mbit chips to give you 128 MBytes of memory on a video card.
So doesn't that give you 8 * 4 Gbytes/sec = 32 GBytes/sec raw speed?
By my way of thinking at 4 GByte/sec throughput per chip, does that mean you either have:
1) 128 bit bus at 250MHz (doesn't seem that fast) or
2) 256 bit bus at 125 MHz
Does this sort of memory need to be accessed one chip at a time or several banks at once?
Many thanks!!!
Samsung say their 128mbit card can do 4GB/sec (regardless of whether the RAM frequency was say 32 GHz on a 1 bit bus or 32 MHz on a 1,024 bit bus).
http://www.samsungelectronics.com/news/device_solution/com_news_1026373517250_001600.html
Seoul, Korea – July 10, 2002: Samsung Electronics Co, Ltd. introduces the industry’s first graphics memory chip using the next-generation DDR II specifications. Samsung’s new graphics chip is available in 128Mb density and boasts a data transmission rate of 1-GigaHertz and higher. The device is capable of transmitting 4-Gigabytes of data per second and is ideally suited for systems that require high memory speed and performance such as 3D graphics, gaming and network applications.
Well I guess you'd need 8 seperate 128 Mbit chips to give you 128 MBytes of memory on a video card.
So doesn't that give you 8 * 4 Gbytes/sec = 32 GBytes/sec raw speed?
By my way of thinking at 4 GByte/sec throughput per chip, does that mean you either have:
1) 128 bit bus at 250MHz (doesn't seem that fast) or
2) 256 bit bus at 125 MHz
Does this sort of memory need to be accessed one chip at a time or several banks at once?
Many thanks!!!