Magnitude and direction of change in velocity. Dont know how to get direction.

[shazam]

1. The problem statement, all variables and given/known data

2. Relevant equations

I used:

square root of: 196^2+236^2-2(196)(236)cos(45)

to get the change in velocity of 169.4

and then did 169.4/5 hours to get the average acceleration of 33.9

3. The attempt at a solution

i don't know what to do for the second one

 

[Blazkowicz]

it's not 45°?

 

[KimB]

I'd just resolve the vectors into components. It then becomes relatively easy to compute the change in direction, as it's a simple subtraction, from which the angle can be computed with an inverse tangent.

P.S. I won't say the actual answer, but the change in velocity is greater than 90° west of north. As the problem suggests, drawing the initial and final velocity vectors will help to see this.