How Many Fragment Pipelines Does G70 Really Have?

Discussion in 'Beyond3D News' started by Dave Baumann, Jun 24, 2005.

  1. Geo

    Geo Mostly Harmless
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    I think more than "does not lend credence" --I think it positively lends credence to the opposite. If we are dealing with two hidden quads, then if this report is true you'd be using three-bad (out of eight) quad parts to make them.

    Cheaper parts are by definition higher volume --how many "three out of eight bad" could they have?

    Altho. . .if you look at 9500Pro as an example, it is not impossible that you could be looking at a marketing-driven move rather than a technically driven move. I guess we'd find out when people try unlocking their extra quads how many of them are actually "bad". This would suggest the yields for G70 are really quite good if they can afford to do that this early.
     
  2. _xxx_

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    1 bad out of 8 would suffice ;)
     
  3. Arun

    Arun Unknown.
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    3 out of 8 seems very possible to me. Remember there IS such a thing as a 8 pipelines NV4x based on the NV40 chip, which has 16 pipelines on the die: the GeForce 6800LE.

    Related links
    3D Table: http://www.beyond3d.com/misc/chipcomp/?view=boarddetails&id=160
    Available in OEM Desktops: http://www.evesham.com/PCs/Info.asp?e=5710C315-1A29-4D1F-AEAF-7B84119F6DE9
    Available in retail: http://www.pricewatch.com/prc.aspx?i=37&a=146149 (Available in retail)
    At least 4 pipelines tend to be unlockable: http://www.ocrig.com/index.php/guides/6800-guide/
    The Inq's history of the board: http://www.theinquirer.net/?article=18960
    Enjoy :)

    Uttar
     
  4. ChrisRay

    ChrisRay <span style="color: rgb(124, 197, 0)">R.I.P. 1983-
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    In my experience with disabling/enabling quads on the 6800GT cards and 7800GTX card this is not the case. Usually they do quite well at reaching there theoretical fillrates even with quads disabled.
     
  5. Verte[X]

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    transistors vs. manufacturing process

    I'm a little late, but I'd like to make a suggestion. If you have a look at ATi's 130nm vs. 110nm process shift (R420 to R430), you can see a 1,17x die size per transistor shrink. To be exact, R420 needs 281mm2 for the same number of transistors as R430 needs 240mm2 for. Now lets compare NV40 and G70 - NV40 has 222M at the die size of 287mm2, that means cca 129,3mm2 per 100M, and G70 has 302M at 334mm2, which is about 110,6mm2 per 100M. You see a 1,17x shrink again so if the ATi's and nVidia's process are roughly similar, then nVidia cannot be lying about the transistor count.

    Therefore, the difference between NV40 and G70 is 80M. If most of the NV40's die size is used for pipelines, let's say about 80%, then there are about 8M transistors for each pipeline (with approximation of vertex and pixel pipe size). Now it seems, that there are only 10 new pipes in the G70, which perfectly corrensponds with 2 new quads and 2 vertex pipes.

    What do you think?
     
  6. YeuEmMaiMai

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    At lower resolutions it would be helpful but not at higher ones
     
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